Multiple choice general knowledge math & puzzles

If both 11^2 and 3^3 are factors of the number a * 4^3 * 6^2 * 13^11, then what is the smallest possible value of a?

  1. 121

  2. 3267

  3. 363

  4. 33
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The number must contain 11^2 and 3^3. The current expression is a * (2^2)^3 * (2*3)^2 * 13^11 = a * 2^8 * 3^2 * 13^11. To have 11^2 and 3^3 as factors, 'a' must provide 11^2 and one more 3 (since we have 3^2). Thus, a = 121 * 3 = 363.

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