Multiple choice The XOR operator is associative and commutative distributive over AND operator both (1) and (2) none of the above Reveal answer Fill a bubble to check yourself A Correct answer Explanation XOR is associative: (A ⊕ B) ⊕ C = A ⊕ (B ⊕ C). XOR is commutative: A ⊕ B = B ⊕ A. However, XOR is NOT distributive over AND - A ⊕ (B·C) ≠ (A ⊕ B)·(A ⊕ C). Therefore only statement (1) is correct.