Analyzing the relationship with sKn and hiF. Option D provides SkN and HIf. Checking ?→sKn: If ? is SkN, then S→s (case inverted), k→k (same), N→n (+1, case inverted). For hiF→?: If ? is HIf, then h→H (case inverted), i→i (same), F→f (case inverted). The pattern involves case inversion with specific positional shifts.