Multiple choice

Calculate the normality of a solution obtained by mixing 100 ml (N/10) H2SO4, 50 ml (N/5) HNO3 and 25 ml (N/5) HCl solution.

  1. 0.3234

  2. 0.4453

  3. 0.545

  4. 0.2286

  5. 0.1123
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the final normality be N. Total volume = (100 + 50 + 25) ml =175 ml So, 175 * N = N1V1 + N2V2 + N3V3------(1) Where, N1, N2, N3 are the normalities of H2SO4, HNO3 and HCl respectively. And V1, V2, V3 are the volumes of H2SO4, HNO3 and HCl respectively. Now, we have, 175 * N = ((100)(1 / 10)) + ((50)(1 / 2)) + ((25)* (1 / 5) = 40 therefore, N = 40 / 175  [where, N = normality of the mixture solution] = 0.2286, which is the required solution of the given problem, hence this is a correct option.

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