Multiple choice

What is the mass of sodium bromate and molarity of the solution necessary to prepare 85.4 ml of 0.672 N solution when the half reaction is, BrO3– + 6H+ + 6e → Br– + 3H2O.

  1. 1.672 g, 0.112 M

  2. 2.0 g, 0.112 M

  3. 3.234 g, 0.112 M

  4. 1.92 g, 0.122 M

  5. 1.446 g, 0.122 M
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Molecular mass of NaBrO3 = 151 Each bromate ion takes up 6 electrons; therefore Eq. mass of NaBrO3 = Mol. mass / 6 = 151 / 6 Amount of NaBrO3 in 85.5 ml 0.672 N solution= (0.672 / 1000) * (151 / 6) * (85.5) g = 1.446 g. Molarity = (Normality / nf) = 0.672 / 6 = 0.112 M. Hence, this is a correct option.

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