Multiple choice general knowledge math & puzzles

find the sum of all number divisible by 6 between 100 to 400

  1. 12000

  2. 12444

  3. 12450

  4. 12456
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C Correct answer
Explanation

The numbers form an arithmetic progression starting at 102 and ending at 396. Using $a=102$, $l=396$, and $d=6$, the number of terms $n$ is $\frac{396-102}{6} + 1 = 50$. The sum is $S_n = \frac{n}{2}(a + l) = \frac{50}{2}(102 + 396) = 25 \times 498 = 12450$. Other options result from calculation errors.

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