The sum of the present ages of A and B is 11 times the difference of their ages. Six years hence, the total of their ages will be 15 times the difference of their ages. What is the present age of the older person?

Let the present age of A be x years and that of B be y years. According to question, x + y = 11(x - y) -5x + 6y = 0 --------------------(1) Six years hence, age of A = x + 6 and that of B = y + 6 years Again, according to question, (x + 6) + (y + 6) = 15[(x + 6) - (y + 6)]

• 7x + 8y = -6 --------------------(2) On solving equations (1) and (2), we get x = 18 and y = 15 So, the age of the older person is 18 years. Correct Answer: 18 years