Multiple choice

The difference of the ages of a father and his son is 18 years. After 6 years, the sum of their ages will be 54 years. Find the product of their ages 10 years ago.

  1. 40 years2

  2. 36 years2

  3. 39 years2

  4. 38 years2

  5. 50 years2

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A Correct answer
Explanation

Let the present age of son be x years. Then, present age of father = (x + 18) years After 6 years, son's age = (x + 6) years and father's age = (x + 18 + 6) years = (x + 24) years Now, according to question, (x + 6) + (x + 24) = 54 2x + 30 = 54 x = 12 So, present age of son = 12 years and present age of father = 12 + 18 = 30 years Ten years ago, father's age = 30 - 10 = 20 years and son's age = 12 - 10 = 2 years Now, product of their ages = 20 years x 2 years= 40 years2