Multiple choice

Which of the following complexes cannot exhibit geometrical isomerism? i. [Ni(CN)4]2-
ii. [Zn(NH3)2Cl2] iii. [Pt(NH3)2Cl2]
iv. [Cr(NH3)6]3+

  1. i and ii only

  2. ii and iii only

  3. i, ii and iv only

  4. ii, iii and iv only

  5. iii and iv only
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

[Ni(CN)4]2- homoleptic complex with tetrahedral geometry. Homoleptic complex does not show geometrical isomerism. [Zn(NH3)2Cl2] is a heteroleptic complex with tetrahedral geometry. Tetrahedral complex does not exhibit geometrical isomerism, as all the four ligand positions are equivalent. [Pt(NH3)2Cl2] is a heteroleptic  square planar complex of Ma2b2 type. In a square planar complex of formula [Ma2b2], the two similar ligands may be arranged adjacent to each other in a cis isomer or opposite to each other in a trans isomer. [Co(NH3)6]3+homoleptic complex ion with octahedral geometry. Homoleptic complex does not show geometrical isomerism.

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