Multiple choice

If a radioactive sample shows 184965 count per minute (cpm), and the efficency of the scintillator is 95.7%, what is the actual radioactivity in curie?

  1. 870.611 x 10-10 ci

  2. 193275 ci

  3. 32221 ci

  4. 17701150 ci

  5. 184965 ci

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Disintegration per minute (dpm)=cpm/efficency. Disintegration per second(dps) = dpm/60. Curie = Dps/3.7*1010.