Multiple choice

Two capacitors of capacitances C1 and C2 are connected across 200 V power supply. The potential drop across C1 is 120 V. A capacitor of capacitance 2µF is connected in parallel with C1 and the potential drop across C2 becomes 160 V. What are the values of V C1 and C2 (in µF)?

  1. 2.4 and 1.6

  2. 0.4 and 0.6

  3. 0.6 and 0.4

  4. 0.6 and 0.13

  5. 0.13 and 0.6

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Initially the charge is same on both capacitors. Therefore, 120 C1 = 80 C2 In the second step, (C1 + 2) 40 = 160 C2. This gives C1 = 0.4 µF and C2 = 0.6 µF.

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