Multiple choice

In capsicum, genotype aabbcc produces 200 gm capsicum and genotype AABBCC produces 260 gm. What will be the contribution of each gene, and what will be the weight of capsicum in progeny, if AAbbcc x aaBBcc?

  1. 20 and 240

  2. 10 and 220

  3. 20 and 280

  4. 10 and 180

  5. None of the above
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Contribution of each gene = (maximum wt - minimum wt ) / number of polygene: (260 - 200 ) / 6 = 10, weight of progeny = ( number of dominant gene x contribution of each gene ) + minimum value. Thus, number of dominant gene in progeny = 2 (AaBbcc), weight of progeny = ( 2 x 10) + 200 = 220.

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