Which of the following represents the real part of ee^iθ?
-
eCosθ (Sin(Sinθ))
-
eCosθ (Cos(Sinθ))
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eSinθ (Sin(Cosθ))
-
eSinθ (Cos(Cosθ))
-
none of these
B
Correct answer
Explanation
e^iθ = (Cosθ + i Sinθ) (According to De Moiver's theorem)
Now, it will become
e(Cosθ + i Sinθ) = (eCosθ)(eiSinθ)
Now, eiSinθ = Cos(Sinθ) + iSin (Sinθ)
So, it will become
eCosθ (Cos(Sinθ) + iSin (Sinθ))
eCosθ (Cos(Sinθ)) + ieCosθ Sin (Sinθ)
Real part is eCosθ (Cos(Sinθ)) (Correct Answer)