Multiple choice

On a graph paper, an insect moves from origin O and covers a distance of 4√3 in the direction of 60° east of north and reaches point A. Then, it turns and moves due south and reaches point B on x-axis and again it turns and reaches to the origin. What is the equation of line OA?

  1. √3x - y = 0

  2. x - √3y = 0

  3. x + √3y = 0

  4. √3x + y = 0

  5. 4√3x - y = 0

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Coordinates of origin are (0,0). Since it moves at point A at a distance of 4√3 from origin in the direction of 60° east of north, hence the coordinates of point A are = (6, 2√3). Now, we are having the coordinates of O and A, we can easily find the equation of line. y-y1=m(x-x1), where m is the slope of the line. m = (y2-y1)/(x2-x1) y1=0, x1=0, y2=2√3, x2=6 m = (2√3/6) = 1/√3 Putting in the equation, we get x-√3y=0 (Correct Answer)