A bird moves from point (1, -2, 3) to (4, 2, 3). If the speed of the bird is 10 m.s-1, then the velocity vector of the bird is:
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5 (i - 2j + 3k)
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5 (4i + 2j + 3k)
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0.6i + 0.8j
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6i + 8j
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3 (i - 2j + 3k)
D
Correct answer
Explanation
Velocity Vector is given by the unit vector in that direction and speed
Initial Point (1, -2, 3)
In Vector Form: (i - 2j + 3k)
Final Point (4, 2, 3)
In Vector Form: (4i + 2j + 3k)
Position Vector can be represented by(4-1)i + (2-(-2))j + (3-3)k(3)i + (4)j----------------(1)
Magnitude = (32+42)1/2
Magnitude = 5-----------(2)
Unit Vector = Dividing (1) by (2)
we get 0.6i + 0.8j
Now speed of the bird = 10 m.s-1
Vector is represented by magnitude and direction
Now magnitude of velocity is speed
So 10 (0.6i + 0.8j) = 6i + 8j (Correct Answer)