Multiple choice

A body is thrown horizontally with a velocity √2gh from the top of a tower of height h. It strikes the level ground through the foot of the tower at a distance x from the tower. The value of x is

  1. h

  2. h/√2

  3. 2h

  4. √2h/√3

  5. h/√3
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Initial vertical component = 0 m.s-1 Distance to be traveled = -h Applying the second equation of motion, -h = 1/2(-g)(t2) t = √(2h/g) Horizontal component of velocity = √2gh Distance = velocity* Time x = √2gh*√(2h/g) = 2h (Correct Answer)

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