Using the cipher RAM→ODJ, each letter shifts forward by position: R(18)+15=O(15), A(1)+3=D(4), M(13)+15=J(10). Applying this pattern to HANUMAN: H(8)+15=E(5), A(1)+3=D(4), N(14)+15=K(11), U(21)+3=X(24), M(13)+15=J(10), A(1)+3=D(4), N(14)+15=K(11), so HANUMAN→EDKXJDK, making the statement true.