Multiple choice

In a family of 5 persons (father, mother, a son and two daughters), 2 are to be selected randomly to go out for dinner. What is the probability that at least one of the daughters is selected for this purpose?

  1. 0.7

  2. 0.4

  3. 0.5

  4. 2/3

  5. 0.2

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A Correct answer
Explanation

2 persons can be selected out of 5 in 5C2 = 10 ways.

Number of selections in which none of the daughters is selected = 3C2 = 3.

In remaining selections (10 – 3 = 7) at least one of the daughters will be present.

So the required probability is, 7/10 = 0.7.