Multiple choice

Enthalpy change(∆H0) for the reaction is given to be +181 kJmol-1 On increasing the temperature,

  1. more nitric oxide will be formed

  2. nitric oxide will dissociates to give nitrogen and oxygen.

  3. equilibrium will be maintained

  4. None of these
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A Correct answer
Explanation

This option is correct and can be explained as follows: Since ∆H0 for the reaction is +ve which means that reaction is endothermic in nature. Hence when temperature is increased then according to Le Chatelier's Principle it favors the forward reaction which nullifies the effect of increase in temperature hence, more nitric oxide is formed.

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