Multiple choice

Consider a reaction I2(s) --------> I2 (in solution). How will the equilibrium shift on addition of more I2(s)?

  1. Equilibrium shifts in forward direction

  2. Equilibrium shifts in backward direction

  3. No change in equilibrium takes place.

  4. Equilibrium shift cannot be predicted

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

This option is correct because I2 is a solid and amount of solid present is not important as long as any equilibrium is present.