Multiple choice

The Henry's law constant, for the solubility of O2 gas in water at 298 K, is 2 atm. The mol fraction of O2 in air is 0.2. The number of moles of O2, from air, dissolved in 10 moles of water at 298 K and 5 atm pressure is:

  1. 20

  2. 10

  3. 1

  4. 15
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Total pressure = 5 atm. By Dalton's Law of partial pressure: P0xygen = (5)*(0.2) = 1 atm. From Henry's Law:POxygen = KH * x1 = 2 * (n/n+10)Solving, n = 10

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