The word INTERNATIONAL has 13 letters. Counting repetitions: I appears 2 times, N appears 3 times, T appears 2 times, A appears 2 times, and E, R, O, L each appear once. The number of distinct arrangements is 13! divided by the factorials of the repetition counts: 13!/(2! × 3! × 2! × 2!) = 6,227,020,800/48 = 129,729,600. Option D is correct. Options A and B ignore repeated letters entirely, while C is irrelevant.