Multiple choice

What combination of IP address and wildcard mask should be used to specify only the last 8 addresses in the subnet 192.168.3.32/28?

  1. 192.168.3.32 0.0.0.7

  2. 192.168.3.32 0.0.0.15

  3. 192.168.3.40 0.0.0.7

  4. 192.168.3.40 0.0.0.15
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C Correct answer
Explanation

The subnet 192.168.3.32/28 has 16 total addresses (32-47), with 14 usable (33-46). The last 8 usable addresses are 192.168.3.40-47. Using the network address 192.168.3.40 with wildcard mask 0.0.0.7 (binary 00000111) matches exactly these 8 addresses: 40 (10101000) AND 7 (00000111) gives the range where the last 3 bits vary, covering 8 addresses total.

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