Multiple choice

A dice is thrown twice. What is the probability of getting number 1 or 5 in the first as well as the second throw?

  1. 1

  2. 7/9

  3. 5/9

  4. 1/3

  5. 1/9
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

In two rolls of a dice, total number of possibilities, i.e. n(S) = (6 x 6) = 36. Let E be an event of getting number 1 or 5 in both the throws = {(1, 1), (1, 5), (5, 1), (5, 5)} or n(E) = 4. Then, the required probability, P(E) = n(E)/n(S) = 4/36 = 1/9 Incorrect answer

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