Multiple choice

How much volume of 0.25 N acid would be required to react with 0.7 gram of Ca(OH)2?

  1. 78.6 ml

  2. 75.6 ml

  3. 85.6 ml

  4. 74.6 ml

  5. 79.6 ml
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Eq. wt. of Ca(OH)2 = 74/2 = 37
Number of gram eq. of Ca(OH)2 in 0.7 gram = 0.7/37  = 0.0189. According to law of equivalence, 0.0189 gm. eq. of Ca(OH)2 will neutralize 0.0189 gm Eq. of acid.     Since,  0.25 gm acid is present in 1000 ml solution.           1 gm acid is present in 1000/0.25 ml solution. 0.0189 gm acid = (1000 x 0.0189)/20.25 = 75.6 ml solution

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