Multiple choice

A proton, when accelerated through a potential difference of V volts, has an associated wavelength of ë. In order, have to the same associated wavelength, an ل-particle must be accelerated thought a potential difference of

  1. V volts

  2. 4 V volts

  3. 2 V volts

  4. V/8 volts
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

De Broglie wavelength λ = h/p = h/√(2mVq) for an accelerated charged particle. For the same λ: √(m₁V₁q₁) = √(m₂V₂q₂). For proton (m, charge e) and alpha particle (4m, charge 2e): √(mV·e) = √(4m·V₂·2e) = √(8mV₂e). This gives V₂ = V/8. The alpha particle needs V/8 volts.

Keep practicing — related questions