Multiple choice

If 10 g of ice at 0°C and 10 g of water at 10°C are mixed, the temperature of the mixture becomes _____.

  1. 0°C

  2. 5°C

  3. 10°C

  4. 16°C
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A Correct answer
Explanation

Heat required to melt 10g ice at 0°C = 10 × 80 = 800 cal. Heat available from 10g water cooling from 10°C to 0°C = 10 × 1 × 10 = 100 cal. Since only 100 cal is available, only 1.25g of ice can melt (100/80). The remaining 8.75g ice stays at 0°C, so final temperature is 0°C with some ice still present.

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