Multiple choice

If $\overrightarrow{E}$= $(\hat{a}+ j \hat{a_y}) e^{jkz - kwt}$and $\overrightarrow{H}$= (k/w$\mu$) $(\hat{a_y}+ k \hat{a_x}) e^{jkz - jwt}$, the time - averaged Poynting vector is

  1. null vector
  2. (k/w$\mu$) $\hat{a_z}$
  3. (2k/w$\mu$) $\hat{a_z}$
  4. (k/2w$\mu$) $\hat{a_z}$
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A Correct answer
Explanation

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