Multiple choice

At what temperature will the root mean square velocity of hydrogen be double of its value at S.T.P. , pressure remaining constant?

  1. 819oC

  2. 1092oC

  3. 1365oC

  4. 819oC

  5. 273oC
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A Correct answer
Explanation

 Let V1 be the r.m.s. velocity at S.T.P. and  V2 be the r.m.s. velocity at unknown temperature T2. Here, T1 = 273 K T2 =?  (V2 / V1 )= 2 V2 rms = 3KT/m We know, v2 ∝ T ∴ V12 / V22 = T1/T2  T2 = T1 (V2 / V1 )2       = 273 x 22       = 273 x 4       = 1092 K T2 = 1092 - 273     =  8190C

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