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The energy band diagram and electron density profile n(x) in a semiconductor are shown in the figure. Assume that n(x) = 105 e$\Big( \frac{q \alpha x}{kT} \Big)$cm–3, with $\alpha$ = 0.1 V/cm and x expressed in cm. Given$\frac{kT}{q}$= 0.026 V, Dn = 36 cm2 s–1, and$\frac{D}{\mu}$=$\frac{kT}{q}$. The electron current density (in A/cm2) at x = 0 is
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