Multiple choice The recursion relative to solve x = e-x using Newton-Raphson method is xn+1 = $e^{-X_n}$ xn+1 = xn -$e^{-X_n}$ xn+1 = (1 + xn) $\frac{e^{-X_n}}{1 + e^{-X_n}}$ xn+1 = $\frac{x_n^2 - e^{-X_n} (1 - X_n) - 1}{X_n - e ^{-X_n}}$ Reveal answer Fill a bubble to check yourself C Correct answer Explanation