Multiple choice

For the circuit shown below, assume that the zener diode is ideal with a breakdown voltage of 6 Volts. The waveform observed across R is

  1.

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Explanation

In forward bias Zener diode works as normal diode. Thus for negative cycle of input Zener diode is froward biased and it conducts giving $V_R = V_in$. For positive cycle of input Zener diode is reversed biased when $0 < V_in < 6$, Diode is OFF and $V_R=0$ when $V_in > 6$ Diode conducts and voltage across diode is 6 V. thus voltage across is resistor is $V_R = V_m -6$

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