Given an orthogonal matrix $\begin{bmatrix}
\ 1 & 1 & 1 & 1 \
\ 1 & 1 & -1 & -1 \
\ 1 & -1 & 0 & 0 \
\ 0 & 0 & 1 & -1
\end{bmatrix}$$\begin{bmatrix}
\ AA^T \
\end{bmatrix}^{-1}$ is
-
$\begin{bmatrix}
\ \frac{1}{4} & 0 & 0 & 0 \\
\ 0 & \frac{1}{4} & 0 & 0 \\
\ 0 & 0 & \frac{1}{2} & 0 \\
\ 0 & 0 & 0 & \frac{1}{2} \\
\end{bmatrix}$
-
$\begin{bmatrix}
\ \frac{1}{2} & 0 & 0 & 0 \\
\ 0 & \frac{1}{2} & 0 & 0 \\
\ 0 & 0 & \frac{1}{2} & 0 \\
\ 0 & 0 & 0 & \frac{1}{2} \\
\end{bmatrix}$
-
$\begin{bmatrix}
\ 1 & 0 & 0 & 0 \\
\ 0 & 1 & 0 & 0 \\
\ 0 & 0 & 1 & 0 \\
\ 0 & 0 & 0 & 1 \\
\end{bmatrix}$
-
$\begin{bmatrix}
\ \frac{1}{4} & 0 & 0 & 0 \\
\ 0 & \frac{1}{4} & 0 & 0 \\
\ 0 & 0 & \frac{1}{4} & 0 \\
\ 0 & 0 & 0 & \frac{1}{4} \\
\end{bmatrix}$
C
Correct answer
Explanation
$\text{From orthogonal matrix}
\\
\begin{bmatrix}
\ AA^T \
\end{bmatrix} = I
\\
\text{Since the inverse of I is I, thus}
\\
\begin{bmatrix}
\ AA^T \
\end{bmatrix} = I^{-1} = I
$