Multiple choice The language recognized by the following finite automation is aabb* + bab* (aab) (empty + (bab)) (aa + empty) (b + ba) (bab)* (aab + ba) (bab)* Reveal answer Fill a bubble to check yourself D Correct answer Explanation Start A to accept $\epsilon$ $r_1 = (aan + ba)$ $\epsilon$ to C & D $r_2 = (bab)^$ $r = r_1r_2 = (aab + ba)(bab)^$