Multiple choice

At a given probability of error, the binary coherent FSK is inferior to binary coherent PSK by

  1. 6 dB

  2. 3 dB

  3. 2 dB

  4. 0 dB
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

We have $P_c = \dfrac{1}{2} erfc \left( \sqrt {\dfrac{E_d}{2\eta}} \right)$

Since $P_\epsilon$ of Binary FSK is 3 dB inferior to binary PSK

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