Multiple choice

Suppose that the modulating signal is m(t) = 2cos (2$\pi$fmt) and the carrier signal is xC(t) = AC cos(2$\pi$fCt), which one of the following is a conventional AM signal without over-modulation?

  1. x(t) = Acm(t) cos(2$\pi$fct)
  2. x(t) = Ac[1 + m(t)]cos(2$\pi$fct)
  3. x(t) = Ac cos(2$\pi$fct) + $\dfrac{A_0}{4}$m(t) cos (2$\pi$fCt)
  4. x(t) = Ac cos(2$\pi$fmt) cos(2$\pi$fct) + Ac sin(2$\pi$fmt) sin(2$\pi$fct)
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation