The dual of the expression derived in the following table is
| $C$ | $\bar C$ | ||
|---|---|---|---|
| $\bar A$ | $\bar B$ | 0 | 0 |
| $\bar A$ | $ B$ | 1 | 1 |
| $\bar A$ | $\bar B$ | 1 | 1 |
| $A$ | $\bar B$ | 0 | 1 |
Reveal answer
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The dual of the expression derived in the following table is
| $C$ | $\bar C$ | ||
|---|---|---|---|
| $\bar A$ | $\bar B$ | 0 | 0 |
| $\bar A$ | $ B$ | 1 | 1 |
| $\bar A$ | $\bar B$ | 1 | 1 |
| $A$ | $\bar B$ | 0 | 1 |