Multiple choice The solution to the recurrence equation $T(2^k) = 3T(2^{k-1})+1, T(1) =1$ is $2^k$ $\frac{(3^{k+1}-1)}{2}$ $3^{\log_2 k}$ $2^{\log_3 k}$ Reveal answer Fill a bubble to check yourself B Correct answer Explanation