If A = $
x = \left[
\begin{array}
\ -2 & 2 \\
1 & -3
\end{array}
\right]
$, then sin At is
-
$\dfrac{1}{3}$$
x = \left[
\begin{array}
\ sin(-4t) + 2sin(-t) - 2sin(-4t) + 2sin(-t) \\\\
-sin(-4t) + sin(-t)2sin(-4t) + sin(-t)
\end{array}
\right]
$
-
$\left[
\begin{array}
\ sin(-2t) sin(2t) \\\\
sin(t) sin(-3t)
\end{array}
\right]$
-
$\dfrac{1}{3}$$
x = \left[
\begin{array}
\ sin(4t) + 2sin(t) 2sin(-4t) - 2sin(-t) \\\\
-sin(-4t) + sin(t)2sin(4t) + sin(t)
\end{array}
\right]
$
-
$\dfrac{1}{3}$$
x = \left[
\begin{array}
\ cos(-t) + 2cos(t) 2cos(-4t) + 2cos(-t) \\\\
-cos(-4t) + cos(-t)-2cos(-4t) + cos(-t)
\end{array}
\right]
$