Consider the following program fragment for reversing the digits in a given integer to obtain a new integer.
Let n = d1 d2 ………… dm
int n, rev;
rev = 0;
while (n < 0) {
rev = rev * 10 + n % 10;
n = n / 10;
}
The loop invariant condition at the end of the ith iteration is
Reveal answer
Fill a bubble to check yourself
