After constructing a max-heap in the heap sort, the time to extract maximum element and then heapifying the heap takes $\Theta$(log n) time by which we could say that $\Theta$ (log n) time is required to correctly place an element in sorted array. If $\Theta$ (logn) time is taken to sort using heap sort, then number of elements that can be sorted is constant which is $\Theta$ (1).