Multiple choice

The circuit shown in a

  1. low pass filter with f3dB = $\dfrac{1}{(R_1 + R_2)C}rad/s$
  2. high pass filter with f3dB = $\dfrac{1}{(R_1)C}rad/s$
  3. low pass filter with f3dB = $\dfrac{1}{(R_1)C}rad/s$
  4. high pas filter with f3dB = $\dfrac{1}{(R_1 + R_2)C}rad/s$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Keep practicing — related questions