Given f1, f3 and f in canonical sum of products form (in decimal) for the circuit.
$f_1 = \Sigma m(4, 5, 6, 7, 8)$
$f_3 = \Sigma m(1, 6, 15)$
$f = \Sigma m(1, 6, 8, 15)$
Then f2 is
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Given f1, f3 and f in canonical sum of products form (in decimal) for the circuit.
$f_1 = \Sigma m(4, 5, 6, 7, 8)$
$f_3 = \Sigma m(1, 6, 15)$
$f = \Sigma m(1, 6, 8, 15)$
Then f2 is