Multiple choice

Given f1, f3 and f in canonical sum of products form (in decimal) for the circuit.

$f_1 = \Sigma m(4, 5, 6, 7, 8)$ $f_3 = \Sigma m(1, 6, 15)$ $f = \Sigma m(1, 6, 8, 15)$

Then f2 is

  1. $\Sigma m(4, 6)$
  2. $\Sigma m(4, 8)$
  3. $\Sigma m(6, 8)$
  4. $\Sigma m(4, 6, 8)$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation