A little observation of the adjacent vertices of different subsets reveals that the maximum degree will be
possessed by a subset of size $\dfrac{n}{2}$.
Suppose an example to compute the maximum degree.
Set is {1,2,3,4,5,6}
We have a subset of size $\dfrac{n}{2}${1,2,3}
Now let us compute its degree
The number of adjacent subsets of size
2 = 3C2 = 3
For each one of {1,2} {2,3} and {1,3}
There are 3 subsets of size 3 which are adjacent to {1,2, 3}
e.g {1,2,4}, {1,2,5}, {1,2,6}
{2,3,4} {2,3,5} {2,3,6}
In this way, for each of {1,2}, {2,3} and {1,3} there are 3C2 subsets of size 5 for each of the three.
The set itself would not be adjacent to {1,2,3}
$\therefore$The maximum Degree = 3 + 3 x 3 + 3 x 3 + 3 = 24
$\therefore \binom{n/2}{2}2^{n/2}$= 3C2 23 = 3 x 8 = 24