Multiple choice

A logical binary relation $\odot$, is defined as follows:

$A$ $B$ $A\odot B$
True True True
True False True
False True False
False False True

Let $\sim$ be the unary negation (NOT) operator, with higher precedence then $\odot$.

Which one of the following is equivalent to $A\wedge B$ ?

  1. $(\sim A\odot B)$
  2. $\sim(A \odot \sim B)$
  3. $\sim(\sim A\odot\sim B)$
  4. $\sim(\sim A\odot B)$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

|||||| |---|---|---|---|---| | A| B| A $\odot$ B| ~ (~ A $\odot$ B)| A $\odot$ B| | T| T| T| ~F=T| T| | T| F| T| ~T=F| F| | F| T| F| ~T=F| F| | F| F| T| ~T=F| T|

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