Multiple choice

Host A is sending data to host B over a full duplex link. A and B are using the sliding window protocol for flow control. The send and receive window sizes are 5 packets each. Data packets (sent only from A to B) are all 1000 bytes long and the transmission time for such a packet is 50 micro second. Acknowledgement packets (sent only from B to A) are very small and require negligible transmission time. The propagation delay over the link is 200 micro second. What is the maximum achievable throughput in this communication?

  1. 7.69 × 106 bps

  2. 11.11 × 106 bps

  3. 12.33 × 106 bps

  4. 15.00 x 106 bps
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Data packet size = 1000 byte        Number of packets = 5        Total data = 5000        Transmission time = 50 micro second/packet        Propagation delay = 200 micro second        So for 5 packets = 50 * 5 = 250 micro second        Total time for 5 packets = 250 + 200 = 450 micro second        Rate = Data/time = 5000*1000000/450 = 11.11*1000000 bps

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