Multiple choice

Passage

Directions: Read the following information and answer the given question. Reema, Mahesh and Suresh are working as a team to complete a treasure hunt task in fun activities organised during college fest. Reema takes 5 more days than Mahesh and 9 more days than Suresh. Reema and Mahesh together can complete the project in the same time as Suresh.

Reema, Mahesh and Suresh all worked together for one day. After this, the least efficient person from the group left and the remaining task is completed by two persons only. Keeping this condition in mind, calculate the time in which the task would be completed.

  1. 2 days

  2. 3 days

  3. 2.5 days

  4. 3.5 days

  5. 4 days
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let M be Mahesh's days, R = M+5, S = M-4. Reema and Mahesh together: 1/(M+5) + 1/M = 1/(M-4). Solving this gives M = 10. So R=15, M=10, S=6. Total work = 30 units. Rates: R=2, M=3, S=5. Total rate = 10. After 1 day, 10 units done, 20 left. Least efficient (Reema) leaves. Remaining: M+S = 8. Time = 20/8 = 2.5 days. Total time = 1 + 2.5 = 3.5 days.

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