Multiple choice

Passage

Study the following information carefully to answer the questions. In a comparative study of population of six states. A, B, C, D, E and F the following were observed. Female population of state A is 120% of the male population of state C and 90% of the female population of state D. Male population of state B is 125% of the male population of state D and 1 11/14 times of the male population of state E. Male and female populations of state D are in the ratio of 13 : 12 respectively. Male population of state A is 5/11th of the total population of the state which is 198000. Female population of state C is 110% of the female population of state A and 75% of the male population of state F. Male and female populations of state E are in the ratio of 7 : 8 respectively. Female population of state B is 150% of the male population of state A. Female population of state F is equal to the male population of state D.

Male population of state A is what percent more or less than female population of state B?

  1. 14 2/7%

  2. 16 2/3%

  3. 25 2/3%

  4. 33 1/3%

  5. 28 2/7%
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Male population of A is 5/11 of 198,000, which is 90,000. Female population of A is 120% of male C, but we need female B. Female B is 150% of male A, so 1.5 * 90,000 = 135,000. The question asks for the percentage difference between male A (90,000) and female B (135,000). The difference is 45,000, which is 45,000/135,000 = 1/3 or 33 1/3% less.

AI explanation

The male population of state A is 5/11 of 198000, which equals 90000. The female population of state B is 150% of the male population of state A, so 1.5 times 90000 equals 135000. Using the percentage difference formula, (135000 minus 90000) divided by 135000 equals 0.3333, making the male population of state A 33 1/3% less than the female population of state B.

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