Multiple choice

Passage

Directions: Study the following data carefully and answer the question that follows. A dishonest petrol dealer mixed some kerosene in petrol and sold it to three customers, P, Q, and R, in the same order. After mixing, the ratio of petrol to kerosene became 9:2, respectively. The table below shows how the exchange took place (The dealer sold 220 litres to person P and then he added 80 litres of petrol and 40 litres of kerosene. The same is given for Q and R). Customers Quantity sold (I) Petrol added (I) Kerosene added (I) Mixture left (I) P 220 80 40 1000 Q y 36 34 M R 260 25r 5r z

If the difference between petrol and kerosene in the final mixture after selling to 'R' is 250 litres, then find the value of 'r'. If the ratio of petrol to kerosene with the dealer just before selling to R is 10 : 3.

  1. 2

  2. 3

  3. 4

  4. 5

  5. None of these
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A Correct answer
AI explanation

Let the quantity of mixture before selling to R be M, which has petrol equal to (10/13)M and kerosene equal to (3/13)M. After selling 260 litres of this 10:3 mixture, the remaining petrol is (10/13)M minus 200 and the remaining kerosene is (3/13)M minus 60. The dealer then adds 25r litres of petrol and 5r litres of kerosene, resulting in a final mixture where the difference between petrol and kerosene is 250 litres. Using the known value M = 650, the remaining petrol is 300 and remaining kerosene is 90, so the equation becomes (300 + 25r) minus (90 + 5r) equals 250. Solving 210 + 20r equals 250 gives 20r = 40, so r = 2.

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