Multiple choice

Passage

Directions: Study the following data carefully and answer the question that follows. A dishonest petrol dealer mixed some kerosene in petrol and sold it to three customers, P, Q, and R, in the same order. After mixing, the ratio of petrol to kerosene became 9:2, respectively. The table below shows how the exchange took place (The dealer sold 220 litres to person P and then he added 80 litres of petrol and 40 litres of kerosene. The same is given for Q and R). Customers Quantity sold (I) Petrol added (I) Kerosene added (I) Mixture left (I) P 220 80 40 1000 Q y 36 34 M R 260 25r 5r z

If the quantity of the mixture right before selling to P was 'X' litres, then find the value of X.

  1. 950

  2. 1000

  3. 1100

  4. 1250

  5. 1300
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The mixture ratio is 9:2 (petrol:kerosene). After selling 220L to P, 1000L remains. Before selling to P, the dealer added 80L petrol and 40L kerosene to the previous mixture. Let the initial mixture be M. M - 220 + 120 = 1000. M = 1100.

AI explanation

Let the initial volume before selling to P be X litres. Since the ratio of petrol to kerosene is 9:2, the mixture contains (9/11) times X of petrol and (2/11) times X of kerosene. After selling 220 litres, the remaining petrol is (9/11)X minus 180 and the remaining kerosene is (2/11)X minus 40. Adding 80 litres of petrol and 40 litres of kerosene brings the total volume back to X, so the new quantities are (9/11)X minus 100 of petrol and (2/11)X of kerosene. Because the new ratio of petrol to kerosene is maintained at 9:2 in the 1000 litres left, (9/11)X minus 100 equals 900, which gives X = 1100.

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